## An iron ball is dropped, it falls 153.7 m before hitting the ground…?

Question

A) How much time did it take to hit the ground?

B) What is the velocity just before it hits the ground?

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General Physics
2 years
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## Answer ( 1 )

During the time the ball is falling, its velocity increases at the rate of 9.8 m/s each second. Since the ball is dropped, its initial velocity is 0 m/s. Let’s use the following equation to determine the time.

d = vi * t + ½ * a * t^2, vi = 0

153.7 = ½ * 9.8 * t^2

t = √(153.7 ÷ 4.9)

This is approximately 5.6 seconds. Let’s use the following equation to determine its velocity just before it hits the ground.

vf = vi + a * t, vi = 0

vf = 9.8 * √(153.7 ÷ 4.9)

This is approximately 54.9 m/s.