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What is the Takeoff and Horizontal Speed?

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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 9.0 m from the takeoff point.

 

If the kangaroo leaves the ground at a 20° angle, what is its takeoff speed ?

R (range) = v02 sin2(θ) / g
9.0 m = v02 sin2(20) / 9.81
v0 = 11.7 m/s (takeoff speed)
= 12 m/s

 

What is its horizontal speed?
Horizontal speed
Vx =v0 cos(20)
12cos(20)
= 11.27
=11 m/s

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