## What is its Orbital Period?

**An earth satellite moves in a circular orbit at a speed of 7000m/s?**

**What is its orbital period?**

r = GM/v^{2}

**r**: distance of the satellite from the center of Earth in m

**M** is the mass of Earth: 5.974 x 10^{24}

**v** is the orbital speed: 7000 m/s

**r** = 6.674x 10^{-11} x 5.974 x 10^{24}/7000^{2}

**r** = 8137445 meters from the center of the Earth

and : 8137445 – 6378100 = 1749345 meters from the surface of the Earth (Distance)

*Calculate the orbital period.*

**Time** = Distance/speed

distance : the circumference of the orbit,

2π x 8137445 = 51129074 meters

Time = (51129074)/7000

Time = 7304 seconds

= 2.02 hours

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