**A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 9.0 m from the takeoff point.**

**If the kangaroo leaves the ground at a 20° angle, what is its takeoff speed ?**

R (range) = v_{0}^{2} sin2(θ) / g

9.0 m = v_{0}^{2} sin2(20) / 9.81

v_{0} = 11.7 m/s (takeoff speed)

= 12 m/s

**What is its horizontal speed?**

Horizontal speed

V_{x} =v_{0} cos(20)

12cos(20)

= 11.27

=11 m/s